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Transformer Riddle No.108 - Capacitive Transformer
Why transformer energy transformation principle is based on electromagnetic or inductive as we have seen two inductors representing primary and secondary. ? is it possible to transfer energy by electrostatic or capacitive principle  by maintaining isolation as our original transformer?

Author : Debabrata Das - From: INDIA
Thu, July 28th, 2016 - 11:44
The displacement current
The calculation of the magnetic field of a current distribution can, in principle, be carried out using Ampere's law which relates the path integral of the magnetic field around a closed path to the current intercepted by an arbitrary surface that spans this path:
Ampere's law is independent of the shape of the surface chosen as long as the current flows along a continuous, unbroken circuit. However, consider the case in which the current wire is broken and connected to a parallel-plate capacitor (see Figure 35.1). A current will flow through the wire during the charging process of the capacitor. This current will generate a magnetic field and if we are far away from the capacitor, this field should be very similar to the magnetic field produced by an infinitely long, continuous, wire. However, the current intercepted by an arbitrary surface now depends on the surface chosen. For example, the surface shown in Figure 35.1 does not intercept any current. Clearly, Ampere's law can not be applied in this case to find the magnetic field generated by the current.

Although the surface shown in Figure 35.1 does not intercept any current, it intercepts electric flux. Suppose the capacitor is an ideal capacitor, with a homogeneous electric field E between the plates and no electric field outside the plates. At a certain time t the charge on the capacitor plates is Q. If the plates have a surface area A then the electric field between the plates is equal to (35.2)

The electric field outside the capacitor is equal to zero. The electric flux, [Phi>E, intercepted by the surface shown in Figure 35.1 is equal to (35.3)
If a current I is flowing through the wire, then the charge on the capacitor plates will be time dependent. The electric flux will therefore also be time dependent, and the rate of change of electric flux is equal to (35.4)

Author : Hamid - From: Iran
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